Written by Allen Wyatt (last updated April 21, 2018)
This tip applies to Excel 97, 2000, 2002, and 2003
Adam has two workbooks; call them A and B. In workbook A he has a link to a value in a PivotTable that is in workbook B. When he opens workbook A and workbook B is not open, Adam gets a #REF! error for the link. He wonders if there is any way to avoid getting the error when linking to a PivotTable value in a workbook that is not open.
There are a couple of ways you can approach this problem. Both methods involve understanding how Excel references the PivotTable value in workbook A. When you create a link to the value and both workbook A and workbook B are open, the reference will look something like this:
=GETPIVOTDATA("TotalValue",'C:\XLDocs\[MyData.xls]PTable'!$H$15,"EName","Rac")
One way to handle the problem is to envelope the reference within an IF statement, in this manner:
=IF(ISERROR(=GETPIVOTDATA("TotalValue",'C:\XLDocs\[MyData.xls]PTable'! $H$15,"EName","Rac")),"Make sure Workbook B is Open", =GETPIVOTDATA( "TotalValue",'C:\XLDocs\[MyData.xls]PTable'!$H$15,"EName","Rac"))
The formula checks the result of the GETPIVOTDATA function, and if it returns an error value (like when workbook B is not open), it displays a message. Only if there is no error value will the value in workbook B be fetched.
Another way is to modify the original reference so that the GETPIVOTDATA function is not being used. (It is this particular function that is generating the error when workbook B is not open.) Here's the way you should redo the reference so that the value is referenced directly instead of through a function:
='C:\MyWork\XLDocs\[MyData.xls]PTable'!$H$15
When the reference is rewritten in this manner, the error condition isn't returned.
ExcelTips is your source for cost-effective Microsoft Excel training. This tip (10649) applies to Microsoft Excel 97, 2000, 2002, and 2003. You can find a version of this tip for the ribbon interface of Excel (Excel 2007 and later) here: Error in Linked PivotTable Value.
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