Most of Excel's worksheet functions can be accessed in VBA by using the WorksheetFunction object. Some functions may not seem to be available, however. One such function is BIN2DEC, which converts a binary value to a decimal value. The reason it isn't available is that BIN2DEC isn't really an Excel worksheet function—it is part of the Analysis ToolPak add-in.
That being the case, you have two options: you can either load the VBA equivalent of the Analysis ToolPak, or you can create your own BIN2DEC function in VBA. To do the first, make sure that in Excel you install the Analysis ToolPak — VBA add-in. If it is not listed in the available add-ins, use Windows to search for the file ATPVBAEN.XLA. (If you are using a language version of Excel other than English, then the "EN" portion of the file will be different.) This is the actual add-in you want to enable.
Once you've enabled the add-in, display the VBA Editor and choose Tools | References to display the References dialog box. Make sure the atpvbaen.xla reference is selected. Close the dialog box, and you can then use BIN2DEC just like you would any other worksheet function.
The other option is to create your own BIN2DEC function. The following is an example of a function that accepts a string that contains the binary digits and returns a numeric value that represents the decimal value of that string.
Function Bin2Dec(sMyBin As String) As Long
Dim x As Integer
Dim iLen As Integer
iLen = Len(sMyBin) - 1
For x = 0 To iLen
Bin2Dec = Bin2Dec + _
Mid(sMyBin, iLen - x + 1, 1) * 2 ^ x
Next
End Function
This function actually doesn't have the same limitations as the BIN2DEC worksheet function; it will work with binary numbers containing more than 10 digits.
Note:
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2020-05-18 16:39:46
niyi
Hi Allen,
I tried using this function on vba for Mac but I'm getting an overflow error on this line -
Bin2Dec = Bin2Dec + Mid(sMyBin, iLen - x + 1, 1) * 2 ^ x.
Possible you check it out?
Thanks.
2013-08-10 05:02:15
Rick Rothstein (MVP - Excel)
Oh, I just remembered I had the companion function hanging around, so here it is as well...
' The DecimalIn argument is limited to 79228162514264337593543950266
' (approximately 96-bits) - large numerical values must be entered
' as a String value to prevent conversion to scientific notation.
Function DecToBin(ByVal DecimalIn As Variant, _
Optional NumberOfBits As Variant) As String
DecToBin = ""
DecimalIn = CDec(DecimalIn)
Do While DecimalIn <> 0
DecToBin = Trim$(Str$(DecimalIn - 2 * Int(DecimalIn / 2))) & DecToBin
DecimalIn = Int(DecimalIn / 2)
Loop
If Not IsMissing(NumberOfBits) Then
If Len(DecToBin) > NumberOfBits Then
DecToBin = "Error - Number too large for bit size"
Else
DecToBin = Right$(String$(NumberOfBits, "0") & DecToBin, NumberOfBits)
End If
End If
End Function
2013-08-10 04:59:42
Rick Rothstein (MVP - Excel)
While this may be considered overkill by some ;-) I thought I would post it anyway...
' BinaryString argument can be a maximum of 96 digits (either 0's or 1's)
Function BinToDec(BinaryString As String) As Variant
Dim X As Integer
Const TwoToThe48 As Variant = 281474976710656#
For X = 0 To Len(BinaryString) - 1
If X > 48 Then
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, Len(BinaryString) - _
X, 1)) * TwoToThe48 * CDec(2 ^ (X - 48))
Else
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, _
Len(BinaryString) - X, 1)) * CDec(2 ^ X)
End If
Next
If Len(BinToDec) > 10 Then BinToDec = CStr(BinToDec)
End Function
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