Using BIN2DEC In a Macro

Written by Allen Wyatt (last updated January 2, 2021)
This tip applies to Excel 97, 2000, 2002, and 2003


1

Most of Excel's worksheet functions can be accessed in VBA by using the WorksheetFunction object. Some functions may not seem to be available, however. One such function is BIN2DEC, which converts a binary value to a decimal value. The reason it isn't available is that BIN2DEC isn't really an Excel worksheet function—it is part of the Analysis ToolPak add-in.

That being the case, you have two options: you can either load the VBA equivalent of the Analysis ToolPak, or you can create your own BIN2DEC function in VBA. To do the first, make sure that in Excel you install the Analysis ToolPak — VBA add-in. If it is not listed in the available add-ins, use Windows to search for the file ATPVBAEN.XLA. (If you are using a language version of Excel other than English, then the "EN" portion of the file will be different.) This is the actual add-in you want to enable.

Once you've enabled the add-in, display the VBA Editor and choose Tools | References to display the References dialog box. Make sure the atpvbaen.xla reference is selected. Close the dialog box, and you can then use BIN2DEC just like you would any other worksheet function.

The other option is to create your own BIN2DEC function. The following is an example of a function that accepts a string that contains the binary digits and returns a numeric value that represents the decimal value of that string.

Function Bin2Dec(sMyBin As String) As Long
    Dim x As Integer
    Dim iLen As Integer

    iLen = Len(sMyBin) - 1
    For x = 0 To iLen
        Bin2Dec = Bin2Dec + _
          Mid(sMyBin, iLen - x + 1, 1) * 2 ^ x
    Next
End Function

This function actually doesn't have the same limitations as the BIN2DEC worksheet function; it will work with binary numbers containing more than 10 digits.

Note:

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ExcelTips is your source for cost-effective Microsoft Excel training. This tip (3063) applies to Microsoft Excel 97, 2000, 2002, and 2003.

Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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Comments

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What is two more than 9?

2021-01-02 10:46:42

Rick Rothstein

Not that anyone would ever need to handle the monstrous numbers my function is capable of, I thought I would post it anyway.

' BinaryString argument can be a maximum of 96 digits (either 0's or 1's)
Function BinToDec(BinaryString As String) As Variant
Dim X As Integer
Const TwoToThe48 As Variant = 281474976710656#
For X = 0 To Len(BinaryString) - 1
If X > 48 Then
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, Len(BinaryString) - X, 1)) * TwoToThe48 * CDec(2 ^ (X - 48))
Else
BinToDec = CDec(BinToDec) + Val(Mid(BinaryString, Len(BinaryString) - X, 1)) * CDec(2 ^ X)
End If
Next
If Len(BinToDec) > 10 Then BinToDec = CStr(BinToDec)
End Function

And in case you should need the inverse for this function...

' The DecimalIn argument is limited to 79228162514264337593543950266
' (approximately 96-bits) - large numerical values must be entered
' as a String value to prevent conversion to scientific notation.
Function DecToBin(ByVal DecimalIn As Variant, Optional NumberOfBits As Variant) As String
DecToBin = ""
DecimalIn = CDec(DecimalIn)
Do While DecimalIn <> 0
DecToBin = Trim$(Str$(DecimalIn - 2 * Int(DecimalIn / 2))) & DecToBin
DecimalIn = Int(DecimalIn / 2)
Loop
If Not IsMissing(NumberOfBits) Then
If Len(DecToBin) > NumberOfBits Then
DecToBin = "Error - Number too large for bit size"
Else
DecToBin = Right$(String$(NumberOfBits, "0") & DecToBin, NumberOfBits)
End If
End If
End Function


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