Error Using ATAN2 Function in Macro

by Allen Wyatt
(last updated December 7, 2016)

2

Lars ran into a problem using the ATAN2 function in a macro. He developed a rather complicated set of instructions, only to have VBA generate an error when it tried to use the ATAN2 function. He was able to simplify the macro so he could recreate the problem:

Sub Test()
    Dim A As Double

    Dim C As Double
    Dim E As Double

    A = 5908
    C = 0
    C = -C
    E = 180 / WorksheetFunction.Pi

    MsgBox E * WorksheetFunction.Atan2(C, A)
End Sub

When the code is executed, the error is generated on the line where ATAN2 is executed. Lars was wondering what, exactly, caused the problem.

The problem is apparently related to how you are manipulating the C variable. You first define C as zero, and then negate this value. There is no such thing as negative zero, and when you try to negate the value, Excel apparently balks when that value is subsequently used in the formula.

One way to solve the problem is simply to change the way in which C is transformed to account for zero values. Change the macro so that it looks like this:

Sub Test()
    Dim A As Double

    Dim C As Double
    Dim E As Double

    A = 5908
    C = 0
    If C <> 0 Then C = -C
    E = 180 / WorksheetFunction.Pi

    MsgBox E * WorksheetFunction.Atan2(C, A)
End Sub

Now the macro will work just fine because you are only doing the transform on C if it doesn't equal zero.

It also appears that the error is only generated if C is defined as a floating-point value. If you dimension C as an Integer, then the original macro does not generate an error. This could indicate that the problem is related to how a floating point representation of the non-existent negative zero is internally represented. Since the Integer data type deals strictly with whole numbers, that representation problem does not occur.

You also can get rid of the problem if you declare C as a Variant data type, or if you remove the declaration line altogether (which means that VBA defaults to declaring C as a Variant when it is first used).

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Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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Comments

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What is one more than 5?

2014-03-10 14:19:57

Scott Renz

or
C = 0 - C

Works too.


2014-03-10 14:16:25

Scott Renz

Changeing the line:
C = -C
to
C = -C + 0

Seems to avoid the error.


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