Please Note: This article is written for users of the following Microsoft Excel versions: 97, 2000, 2002, and 2003. If you are using a later version (Excel 2007 or later), this tip may not work for you. For a version of this tip written specifically for later versions of Excel, click here: Finding the Number of Significant Digits.

Finding the Number of Significant Digits

Written by Allen Wyatt (last updated April 6, 2024)
This tip applies to Excel 97, 2000, 2002, and 2003

Brenda is interested in knowing the number of significant digits in a value. She wonders if there is an Excel function or formula she can use that would return the number of significant digits in the value shown in a cell.

This question is not as simple as it seems. For some people, finding the number of digits in a value, less any decimal points or negative signs. If that is all you need, then something like this formula will work just fine:

```=IF(A1<0,IF(A1=INT(A1),LEN(A1)-1,LEN(A1)-2),IF(INT(A1)=A1,LEN(A1),LEN(A1)-1))
```

The reason that this isn't that simple, however, is because what constitutes the number of significant digits in a value depends on many things. The bottom line is that you can't always tell by looking at a value how many significant digits it has.

For instance, the value 100 could have 1, 2, or 3 significant digits. It is presumed that the value 1.00 has 3 significant digits, but that may not be the case if the value displayed is the result of formatting imposed by Excel—for instance, the value in the cell could be 1.0000437, which Excel formats as 1.00. You can discover more about the topic of significant digits here:

```http://excel.tips.net/T001983
```

There are some generally accepted ways to identify significant digits in a number, but any attempt to codify a set of rules is always open to debate. One such set of rules has been noted at Wikipedia, in the "Identifying Significant Digits" section of this article:

```http://en.wikipedia.org/wiki/Significant_figures
```

With at least a rudimentary set of rules in mind (such as the one in the Wikipedia article) it is possible to develop a user-defined function that will give you the most likely number of significant digits for a value.

```Function SigFigs(rng As Range, Optional iType As Integer = 1)
'iType = 1 is Min
'iType = 2 is Max

Dim rCell As Range
Dim sText As String
Dim sText2 As String
Dim iMax As Integer
Dim iMin As Integer
Dim iDec As Integer
Dim i As Integer

Application.Volatile
Set rCell = rng.Cells(1)

'if not a number then error
If Not IsNumeric(rCell) Or IsDate(rCell) Then
SigFigs = CVErr(xlErrNum)
Exit Function
End If

sText2 = Trim(rCell.Text)
sText = ""
'find position of decimal point (it matters)
iDec = InStr(sText2, ".")

'strip out any non-numbers (including decimal point)
For i = 1 To Len(sText2)
If Mid(sText2, i, 1) >= "0" And _
Mid(sText2, i, 1) <= "9" Then _
sText = sText & Mid(sText2, i, 1)
Next

'remove any leading zeroes (they don't matter)
While Left(sText, 1) = "0"
sText = Mid(sText, 2)
Wend
iMax = Len(sText)

'strip trailing zeroes (they don't matter if no decimal point)
sText2 = sText
If iDec = 0 Then
While Right(sText2, 1) = "0"
sText2 = Left(sText2, Len(sText2) - 1)
Wend
End If
iMin = Len(sText2)

'return Min or Max
Select Case iType
Case 1
SigFigs = iMin
Case 2
SigFigs = iMax
Case Else
SigFigs = CVErr(xlErrNum)
End Select
End Function
```

You call this function by using the following in your worksheet:

```=SigFigs(A1, x)
```

You can replace x with either 1 or 2. If you specify 1, then the function returns the minimum number of significant digits. If you specify 2, then the function returns the maximum number of significant digits. In most cases the two possible return values will be the same, except with values that are whole numbers, without a trailing decimal point, that have trailing zeroes. In other words, if you use the function to evaluate the number 1234000, then the minimum (x is 1) returns 4 and the maximum (x is 2) returns 7.

The function takes into consideration how the number appears in the worksheet, meaning that it matters how the number is formatted. It strips out any formatting characters, such as negative signs, parentheses, and commas.

Note:

If you would like to know how to use the macros described on this page (or on any other page on the ExcelTips sites), I've prepared a special page that includes helpful information. Click here to open that special page in a new browser tab.

ExcelTips is your source for cost-effective Microsoft Excel training. This tip (10975) applies to Microsoft Excel 97, 2000, 2002, and 2003. You can find a version of this tip for the ribbon interface of Excel (Excel 2007 and later) here: Finding the Number of Significant Digits.

Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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What is three more than 7?

2024-04-07 06:19:42

Peter

Significant figures and precision of a calculation are dependent on the precision of the starting values/arguments. Quoting the article Allen suggested "Spurious digits that arise from calculations resulting in a higher precision than the original data or a measurement reported with greater precision than the instrument's resolution." This probably applies to a large number of calculations in Excel. As the article suggests rounding is a way to prevent reporting of excessive precision. Working out the rounding is another problem.

Relative error is a fair way to assess precision. Say you know that for a measurement "A" the relative error is ±α, and for B it is ±β. It is likely that A could vary over A*(1±α). Then the product A*B is close to A*B*(1±(α+β)), and the ratio is close to A/B(1±(α+β)). For addition or subtraction it is a bit messier. The value y=A*B or y=A/B should be rounded by y*(α+β) if that were possible.

I can't find a function in Excel that gives calculates significance. Say the result is 77.53 accurate to 2%. That is, (α+β) =0.02 in my examples. 2% of 77.53 is ~0.19, so the result could fall between ~77.31 and ~77.69. I would argue that 77.53 has 3 significant figures in this case.

2024-04-06 06:44:17

jamies

Associated with the problem of significant digits is the way floating point values are stored, and the frequency with which Excel uses that to store results of multiply and divide.
Plus the limitations -
as in add 1 to a large number such as 1234567890543210 and the value does not change.

When testing numeric values for equality it is better to check the remainder of subtracting the 2 is not significant
as in
IF(ABS(val1-val2)<0.0000001,"near enough","different")).

the formula provided
=IF(A1<0,IF(A1=INT(A1),LEN(A1)-1,LEN(A1)-2),IF(INT(A1)=A1,LEN(A1),LEN(A1)-1))

could, perhaps benefit from the use of ABS() and perhaps a test for actually being numeric not a string, or void

Maybe also in the script cater for the radix point being a "," rather than a "."
And, the comment that leading zeroes don't matter if no decimal point - well, if it has been stripped out ?

I would have "counted the characters up to, but excluding the decimal point character, then the count after , using a max of the number of decimal places to count -
that because of the stored value of such as 1/3 and of 0.2

Basically those will always be 16, unless the value is larger than 10^16, when the extra zeroes before the decimal point are significant !

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