**Please Note: **
This article is written for users of the following Microsoft Excel versions: 97, 2000, 2002, and 2003. If you are using a later version (Excel 2007 or later), *this tip may not work for you*. For a version of this tip written specifically for later versions of Excel, click here: Summing Digits in a Value.

Written by Allen Wyatt (last updated January 4, 2020)**This tip applies to** Excel 97, 2000, 2002, and 2003

If you have a cell that contains a value, you may want to devise a way to add together all the digits in the value. For instance, if a cell contains the value 554, you might want to determine the sum of 5+5+4, which is 14.

There are several ways you can approach this task. (Doesn't that always seem the way in Excel?) The first is to use a formula that relies on several functions:

=SUMPRODUCT(--MID(A1,ROW(INDIRECT("1:" & LEN(A1))),1))

This regular formula will sum the digits in any integer value (in cell A1) in a simple, elegant manner. This is not the only possible formula, however. The following is an array formula (terminated by pressing **Ctrl+Shift+Enter**) version of the same formula:

=SUM(1*MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1))

Either of these formulas work fine if the value in A1 is a positive whole number. If there are any non-digit characters in the number (such as a negative sign or a decimal point), then the formulas return a #VALUE! error.

You can also use a user-defined function to return the desired sum. The following macro steps through each digit in the referenced cell and calculates a total. This value is then returned to the user:

Function AddDigits(Number As Long) As Integer Dim i As Integer Dim Sum As Integer Dim sNumber As String sNumber = CStr(Number) For i = 1 To Len(sNumber) Sum = Sum + Mid(sNumber, i, 1) Next AddDigits = Sum End Function

To use this function, just use a formula such as =AddDigits(A1) in a cell. An even more compact user-defined function (invoked in the same manner) is the following:

Function AddDigits(ByVal N As Long) As Integer Do While N >= 1 AddDigits = AddDigits + N Mod 10 N = Int(N / 10) Loop End Function

Unlike the earlier macro, this version doesn't convert the cell contents to a string in order to process it. Instead, it steps through each digit of the value, stripping off the last digit and adding it to the total.

*Note:*

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This tip (2424) applies to Microsoft Excel 97, 2000, 2002, and 2003. You can find a version of this tip for the ribbon interface of Excel (Excel 2007 and later) here: **Summing Digits in a Value**.

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2021-04-11 05:30:20

Willy Vanhaelen

Function AddDigits(Number As String) As Integer

Dim i As Integer, Char As String

For i = 1 To Len(Number)

Char = Mid(Number, i, 1)

If IsNumeric(Char) Then AddDigits = AddDigits + Char

Next

End Function

2021-04-10 09:40:38

Roy

=VALUE(TEXTJOIN("",TRUE,IFERROR(VALUE(MID(A1,SEQUENCE(LEN(A1)),1)),"")))

So "D-55a4" becomes just "554" or just the string "554" if you don't apply the VALUE() fucntion at the end. "-8" becomes "8": you won't retain the idea something was a negative number, but since the digits were your focus, not their values, that isn't an issue.

Side note: if you ever have problems with ABS(), or more likely INT() and related functions, not returning a value axatly as you'd like, it could help you control that better (or not, depending on what your desire is).

Works nicely for stripping non-printing characters from what should be numerical information. Lots of imported data suffers from those and CLEAN() is usually useless for that problem. (Very much a "it was useful in simpler times" kind of function.)

It works with anything Excel builds VALUE() to recognize (just the usual for us in the US, but some other country builds might have VALUE() fucntions that recognize more characters as numerals, and so...).

2021-04-10 09:24:41

Roy

=SUM(IFERROR(VALUE(MID(A1,SEQUENCE(LEN(A1)),1)),0)) (for an imput presented in cell A1)

So only numerals are added, no matter what, and no complications. No macros needed. Something either succeeds inside VALUE() and is added, or does NOT succeed and is effectively ignored by the value used for it being 0.

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