Loading

Got a version of Excel that uses the
menu interface (Excel 97, Excel 2000, Excel 2002, or Excel 2003)?
**This site is for you!** If you
use a later version of Excel, visit
our *ExcelTips* site focusing on the ribbon interface.

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company.

Learn more about Allen...

ExcelTips FAQ

Ask an Excel Question

Make a Comment

Free Business Forms

Free Calendars

** Please Note:** This article is written for users of the following Microsoft Excel versions: 97, 2000, 2002, and 2003. If you are using a later version (Excel 2007 or later),

Dan has a column of cells and each cell contains three items: city, state and ZIP Code. (All three are in a single cell, much like you see in an address line.) Some of the ZIP Codes are five digits and some are nine. Dan needs to pull both the two-character state and the five-digit ZIP Code into their own cells, to the right of the current data. Dan knows he can use the Text to Columns tool, but feels that it involves a lot of work since he would need to deal with multiple-word city names and commas. Dan can't help but think there may be a formulaic approach that would be easier.

There needs to be a few assumptions made about the data in order to make any recommendations. Let's assume, for example, that all the data is in this format:

My Town, CA 98765-4321

The portion from the dash onward (the trailing part of the ZIP Code) is optional, but the position of the comma is static—it always follows the name of the town—and the state always consists of two characters. In this case it is easy to devise two formulas that extract the state abbreviation and the first five digits of the ZIP Code:

=MID(A1,FIND(",",A1)+2,2) =MID(A1,FIND(",",A1)+5,5)

Both formulas key on the comma; it serves as a delimiter between the city and the two items really want. If there is no comma in the data or if there are multiple commas, then the formulas won't return the desired information.

The formulas also assume that there are no extra spaces in your data; at most there is a single space after the comma and between the state and ZIP Code. This is, of course, easy enough to enforce—just use Find and Replace to replace two spaces with a single space anywhere in your worksheet.

Of course, if your data is this structured, you can still rely on the Text to Columns tool to do your work. All you need to do is run the tool and split your data based on the comma. This will leave the city in one cell and put the state and ZIP Code together in the next cell. Then you can use Text to Columns again, this time on the second cell (not the city name) and divide the contents based on the space.

If your data is not that structured—perhaps it has multiple commas in the address or extra spaces—then an entirely different approach is called for. To deal with this the basic technique involves trimming the data to remove extraneous spaces (leading, trailing, and internal), then determining the location of the last space and the second-to-last space.

You can pull out the five digits in the ZIP Code, which is defined as immediately following the last space in the data, by using this formula:

=MID(TRIM(A1),FIND(CHAR(1),SUBSTITUTE(TRIM(A1)," ", CHAR(1),LEN(TRIM(A1))-LEN(SUBSTITUTE(TRIM(A1)," ",""))))+1,5)

The two-character state abbreviation can be returned by pulling out the two characters immediately following the second-to-last space:

=MID(TRIM(A1),FIND(CHAR(1),SUBSTITUTE(TRIM(A1)," ",CHAR(1), LEN(TRIM(A1))-LEN(SUBSTITUTE(TRIM(A1)," ",""))-1))+1,2)

If your data is even less structured—perhaps it includes addresses that don't all have two-character state abbreviations (N.J. instead of NJ)—then you would best be served to use a macro to divide up the data. The reason for this is that VBA has a much richer set of text handling functions than what you can do using Excel formulas. The following macro creates a user-defined function that can return either the state or ZIP Code:

Function GetStateZIP(rstrAddress As String, iAction As Integer) As String Dim arr As Variant Dim sState As String Dim sZIP As String Dim J As Integer Dim K As Integer Application.Volatile rstrAddress = Trim(rstrAddress) If Len(rstrAddress) = 0 Then Exit Function sState = "?" sZIP = "?" For J = Len(rstrAddress) To 1 Step -1 If Mid(rstrAddress, J, 1) = " " And sZIP = "?" Then sZIP = Mid(rstrAddress, J + 1, 5) rstrAddress = Trim(Left(rstrAddress, J)) For K = Len(rstrAddress) To 1 Step -1 If Mid(rstrAddress, K, 1) = " " And sState = "?" Then sState = Mid(rstrAddress, K + 1, 20) rstrAddress = Trim(Left(rstrAddress, K)) End If Next K End If Next J If iAction = 1 Then GetStateZIP = sState End If If iAction = 2 Then GetStateZIP = sZIP End If End Function

To use this function, simply provide a cell reference and either 1 (if you want the state) or 2 (if you want the ZIP Code). Here is an example of requesting the ZIP Code for whatever address is in cell A1:

=GetStateZIP(A1,2)

*ExcelTips* is your source for cost-effective Microsoft Excel training. This tip (9598) applies to Microsoft Excel 97, 2000, 2002, and 2003. You can find a version of this tip for the ribbon interface of Excel (Excel 2007 and later) here: Extracting a State and a ZIP Code.

*Related Tips:*

**Comprehensive VBA Guide** Visual Basic for Applications (VBA) is the language used for writing macros in all Office programs. This complete guide shows both professionals and novices how to master VBA in order to customize the entire Office suite for their needs. Check out *Mastering VBA for Office 2010* today!

You show the formula, but after showing the formula it would be helpful to have an immediate example.

Otherwise I do not know if your formula is using references to your own data or actual excel functions.

Frankly, with a formula that long...I don't have the time to troubleshoot it to figure it out.

Otherwise I do not know if your formula is using references to your own data or actual excel functions.

Frankly, with a formula that long...I don't have the time to troubleshoot it to figure it out.

I tried to revise the macro but receive an error when the Find function is encountered. Could you review the following code and offers some assistance?

Function GetCityStateZIP(rstrAddress As String, iAction As Integer) As String

Dim arr As Variant

Dim sState As String

Dim sZIP As String

Dim sCity As String

Dim J As Integer

Dim K As Integer

Dim L As Integer

Application.Volatile

rstrAddress = Trim(rstrAddress)

If Len(rstrAddress) = 0 Then Exit Function

sCity = "?"

sState = "?"

sZIP = "?"

For J = Len(rstrAddress) To 1 Step -1

If Mid(rstrAddress, J, 1) = " " And sZIP = "?" Then

sZIP = Mid(rstrAddress, J + 1, 5)

rstrAddress = Trim(Left(rstrAddress, J))

For K = Len(rstrAddress) To 1 Step -1

If Mid(rstrAddress, K, 1) = " " And sState = "?" Then

sState = Mid(rstrAddress, K + 1, 20)

rstrAddress = Trim(Left(rstrAddress, K))

End If

Next K

For L = Len(rstrAddress) To 1 Step -1

If Mid(rstrAddress, L, 1) = " " And sCity = "?" Then

sCity = Left(L, Find(",", L) - 1)

rstrAddress = Trim(Left(rstrAddress, L))

End If

Next L

End If

Next J

If iAction = 1 Then

GetCityStateZIP = sCity

End If

If iAction = 2 Then

GetCityStateZIP = sState

End If

If iAction = 3 Then

GetCityStateZIP = sZIP

End If

End Function

Function GetCityStateZIP(rstrAddress As String, iAction As Integer) As String

Dim arr As Variant

Dim sState As String

Dim sZIP As String

Dim sCity As String

Dim J As Integer

Dim K As Integer

Dim L As Integer

Application.Volatile

rstrAddress = Trim(rstrAddress)

If Len(rstrAddress) = 0 Then Exit Function

sCity = "?"

sState = "?"

sZIP = "?"

For J = Len(rstrAddress) To 1 Step -1

If Mid(rstrAddress, J, 1) = " " And sZIP = "?" Then

sZIP = Mid(rstrAddress, J + 1, 5)

rstrAddress = Trim(Left(rstrAddress, J))

For K = Len(rstrAddress) To 1 Step -1

If Mid(rstrAddress, K, 1) = " " And sState = "?" Then

sState = Mid(rstrAddress, K + 1, 20)

rstrAddress = Trim(Left(rstrAddress, K))

End If

Next K

For L = Len(rstrAddress) To 1 Step -1

If Mid(rstrAddress, L, 1) = " " And sCity = "?" Then

sCity = Left(L, Find(",", L) - 1)

rstrAddress = Trim(Left(rstrAddress, L))

End If

Next L

End If

Next J

If iAction = 1 Then

GetCityStateZIP = sCity

End If

If iAction = 2 Then

GetCityStateZIP = sState

End If

If iAction = 3 Then

GetCityStateZIP = sZIP

End If

End Function

Thanks for sharing these functions and macro. What about pulling out the city name? Is there anyway to include that in a seperate cell?

This article will be easier to understand if it includes a practice file in which I can try and analyze the long formula