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** Please Note:** This article is written for users of the following Microsoft Excel versions: 97, 2000, 2002, and 2003. If you are using a later version (Excel 2007 or later),

Barry often finds himself wanting to identify the Nth occurrence of a character within a text string. He knows he can use the SEARCH and FIND worksheet functions for finding an initial occurrence, but is unsure how to find, say, the 3rd occurrence of the letter "B" within a text string.

Actually, the SEARCH function could be used to find the desired occurrence, in the following manner:

=SEARCHB("b",G20,(SEARCHB("b",G20,(SEARCHB("b",G20,1)+1))+1))

Notice how the SEARCHB function is used in a nested manner. The formula specifies what is being searched for (the letter "b") and the number of nesting levels indicates which occurrence within the cell you want to find. The formula returns the position of the desired character within the cell.

The problem with such a formula, of course, is that it is difficult to maintain and can quickly get unusable if you want to find, say, the seventh occurrence.

A more flexible formula would be the following:

=FIND(CHAR(1),SUBSTITUTE(A1,"B",CHAR(1),3))

This formula examines the value in A1. It substitutes the CHAR(1) code for the third occurrence of "B" within the cell. The FIND function then looks within the resulting string for the position where CHAR(1) occurs. If the desired occurrence does not exist, then the formula returns a #VALUE error.

If you prefer, you could create a user-defined function that will look for the Nth position of a character. The following is a very simple macro that takes three arguments: the string to be searched, the text to match, and the position desired.

Function FindN(sFindWhat As String, _ sInputString As String, N As Integer) As Integer Dim J As Integer Application.Volatile FindN = 0 For J = 1 To N FindN = InStr(FindN + 1, sInputString, sFindWhat) If FindN = 0 Then Exit For Next End Function

The function is case sensitive in what it searches for, and it returns the position within the specified string at which the sFindWhat value occurs. If there is no occurrence at the specified instance, then the function returns a 0. The following shows how the function can be used in a worksheet:

=FindN("b",C15,3)

*ExcelTips* is your source for cost-effective Microsoft Excel training. This tip (3324) applies to Microsoft Excel 97, 2000, 2002, and 2003. You can find a version of this tip for the ribbon interface of Excel (Excel 2007 and later) here: Finding the Nth Occurrence of a Character.

*Related Tips:*

**Excel Smarts for Beginners!** Featuring the friendly and trusted *For Dummies* style, this popular guide shows beginners how to get up and running with Excel while also helping more experienced users get comfortable with the newest features. Check out *Excel 2013 For Dummies* today!

@Jason,

If I understood you correctly and the pattern of the string stays constant and you prefer to retrieve the 4th. part (after the 3rd. space) - you might consider using a much shorter formula:

=MID(SUBSTITUTE(A1," ",REPT(" ",LEN(A1))),LEN(A1)*3,LEN(A1))*1

Michael (Micky) Avidan

“Microsoft® Answers" - Wiki author & Forums Moderator

“Microsoft®” MVP – Excel (2009-2015)

ISRAEL

If I understood you correctly and the pattern of the string stays constant and you prefer to retrieve the 4th. part (after the 3rd. space) - you might consider using a much shorter formula:

=MID(SUBSTITUTE(A1," ",REPT(" ",LEN(A1))),LEN(A1)*3,LEN(A1))*1

Michael (Micky) Avidan

“Microsoft® Answers" - Wiki author & Forums Moderator

“Microsoft®” MVP – Excel (2009-2015)

ISRAEL

The section "a more flexible formula would be" helped me a great deal!

After hours of searching I finally found a solution to take "88.88" as a number out of the following sample text:

"2015-02-03 77.77 GB 88.88 GB 99.99 GB "

My sample formula ended up being:

=(VALUE((MID($B46,(FIND(CHAR(1),SUBSTITUTE($B46," ",CHAR(1),3))+1),(FIND(CHAR(1),SUBSTITUTE($B46," ",CHAR(1),4)))-(FIND(CHAR(1),SUBSTITUTE($B46," ",CHAR(1),3))+1)))))

As it's being copied across from a RDP session, it comes as plain text.

Thank you so much!

After hours of searching I finally found a solution to take "88.88" as a number out of the following sample text:

"2015-02-03 77.77 GB 88.88 GB 99.99 GB "

My sample formula ended up being:

=(VALUE((MID($B46,(FIND(CHAR(1),SUBSTITUTE($B46," ",CHAR(1),3))+1),(FIND(CHAR(1),SUBSTITUTE($B46," ",CHAR(1),4)))-(FIND(CHAR(1),SUBSTITUTE($B46," ",CHAR(1),3))+1)))))

As it's being copied across from a RDP session, it comes as plain text.

Thank you so much!

Clear, concise, and works perfectly.

Thank you for this.

Thank you for this.

Thanks for this. I've seen the tips before (except using FIND instead of SEARCH), but this explains them better.

Thanks a lot for this tip. I've looking around for a simple formula for this and all of them were messy. Your formula is easy and effective. Thanks again!