 Please Note: This article is written for users of the following Microsoft Excel versions: 97, 2000, 2002, and 2003. If you are using a later version (Excel 2007 or later), this tip may not work for you. For a version of this tip written specifically for later versions of Excel, click here: Determining If a Value is Out of Limits.

# Determining If a Value is Out of Limits by Allen Wyatt
(last updated April 13, 2019)

Jennifer has two numbers that she needs to compare in a formula. If the second number is within 5% (plus or minus) of the first number, it is considered within limits. If the second number is outside of this range, then she needs the formula to return something such as "out of limits."

There are a number of different ways you could approach your formula. Let's assume that your first number is in cell A1 and that the number you want to compare to it is in cell B1. One method is to use the IF function to do your testing:

```=IF((A1-B1)>(A1*0.05),"out of limits",
IF((B1-A1)>(A1*0.05),"out of limits",
"within limits"))
```

This works fine, but the formula is a bit long. You can add the OR function to your formula to make it quite a bit shorter:

```=IF(OR(B1<A1*0.95,B1>A1*1.05),"out of limits","within limits")
```

You could make the formula shorter still by skipping the OR function and simply doing a comparison on the absolute difference between the values:

```=IF(ABS((B1-A1)/A1)<=0.05,"within limits","out of limits")
```

Since there is division happening in this formula, it is possible that you could get an error if the value in A1 is 0. To avoid this potential problem, the formula should be modified slightly:

```=IF(A1=0,"unknown",IF(ABS((B1-A1)/A1)<=0.05,
"within limits","out of limits"))
```

If the requirement is for the values to be "within 5% of each other," the calculation is slightly more complex:

```=IF(ABS(B1-A1)/MAX(ABS(B1),ABS(A1))>0.05,
"out of limits","within limits")
```

In this case, the MAX function is used to determine the larger of the two values in A1 and B1. It must test the absolute values of A1 and B1 because the MAX function returns the value nearest to zero if both numbers are negative.

ExcelTips is your source for cost-effective Microsoft Excel training. This tip (3803) applies to Microsoft Excel 97, 2000, 2002, and 2003. You can find a version of this tip for the ribbon interface of Excel (Excel 2007 and later) here: Determining If a Value is Out of Limits.

##### Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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What is one more than 3?

2019-10-10 12:23:00

I was trying your formula, however, it gives all my values as over budget when I want to see if the value is over or under within a range of 15% of the second value :

=IF(ABS(B1-A1)/MAX(ABS(B1),ABS(A1))>0.15,
"over budget","under budget")

I'm testing two percentages (Actual Expenditure vs Budgeted Expenditure)

If the Value of Cell B is Equal to Cell A then Good, but if Cell B is outside of a range of 20% of the value of Cell B compared with Cell A then flag as Under if it's greater than 20% or Flag Red if it's greater than 20%

A (budget) | B (time elapsed) | C
21.37% | 62.11% Under Budget (is what I'd expect - we should have spent 62% but we've only spent 21% so far)
131.44% | 26.58% Over Budget
1.96% | 14.81% GOOD (within Tolerance)
8.93% | 80.56% Under Budget
87.65% | 6.13% Over Budget
50% | 60% GOOD
60% | 50% GOOD

Is there a way I could do this to allow a tolerance either side of Cell B, within a single formula.

2019-09-03 00:51:26

Phuah

I had facing some problem with the similar formula for =IF(OR(B1<A1*0.95,B1>A1*1.05),"out of limits","within limits"). I had created my sheet with this formula =IF((OR(\$B121:\$B131<\$B131*\$D\$7, \$B121:\$B131>\$B131*\$D\$8)),"1","0") but it facing error on excel with #value after creating 12 cells with this formula.

Is it limitation in excel application bugs?

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