 by Allen Wyatt
(last updated September 27, 2018)

John has a lookup table of ascending numerical values in column A and corresponding text values in column B. When he uses the VLOOKUP function it returns the text value for the numerical value equal to or less than the specified lookup value. John really wants the first value equal to or greater than the lookup value.

There is no way to change how VLOOKUP does its work; it will always match to the value equal to or less than the lookup value. An option, though, is to modify the formula used to do the actual lookup. Consider the following formula, which assumes that the value you want to use for your lookup is in cell D1:

```=IF(VLOOKUP(D1,\$A\$1:\$A\$10,1)=D1,VLOOKUP(D1,\$A\$1:\$B\$10,2),
INDEX(\$B\$1:\$B\$10,1+MATCH(D1,\$A\$1:\$A\$10)))
```

If the value in D1 is an exact match to a value in column A, then the regular VLOOKUP formula is used. If it isn't, then VLOOKUP is abandoned in favor of the INDEX function in conjunction with the MATCH function.

If you are able to sort your data table in descending order, you can use a shorter formula:

```=INDEX(\$A\$1:\$B\$10,MATCH(D1,\$A\$1:\$A\$10,-1),2)
```

The MATCH function uses the D1 value to look for the smallest value that is great than or equal to that value. (This is what the -1 parameter specifies.) The MATCH function returns the row number of the proper row, and then this is used by INDEX to actually fetch the value.

Another interesting approach to the problem is to use the inverse of the lookup values as a control column that will be used to actually look up information from the data table. For instance, let's assume that your data table is in A1:B10, with the actual numerical values you use for the lookup in column A. You need to insert a column to the left of your data table. Into the first cell of this new column (now column A), insert the following formula:

```=1/B1
```

This provides the inverse of the value in B1, and you can copy it down the cells in column A. Your data table now has three columns, A1:C10. Next, sort your data table based on this new column, in ascending order.

Now you make a slight modification to your lookup formula so that it looks up the inverse of what you want. Assuming that the value you want to use for your lookup is in cell E1, you would use the following formula:

```=VLOOKUP(1/E1,\$A\$1:\$C\$10,3)
```

What you effectively end up with is the desired value, from column C, that is associated with the value in column B that is equal to or less than the value in E1.

ExcelTips is your source for cost-effective Microsoft Excel training. This tip (3090) applies to Microsoft Excel 97, 2000, 2002, and 2003.

##### Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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What is four less than 9?

2020-11-15 11:04:03

Larry Ellis

VLOOKUP serves well to handle "from-to" ranges, where the only values needed in the search range are the "from" values.

It does not serve to handle "to" ranges, which is the case described in this article.

The first solution, a combination of INDEX and MATCH for unequal values only, fails if the the search value is lower than the first row of the search range. The second solution, which annoyingly requires the range to be sorted in descending sequence, works correctly.

The newer XLOOKUP function (available only in O365), handles "to" ranges directly, and even without the need for a sort in most cases.

2014-10-09 08:12:26

ashish mehra

If you want to know more about "Index Formula vs. Vlookup Formula", check this link ........

http://www.exceltip.com/lookup-formulas/index-formula-vs-vlookup-formula.html

2014-03-15 19:07:38

Mike Epstein

Sometimes reciprocals cause problems. Why not use the negative instead? After inserting a new column A, type into A1 "=-b1" (instead of "1/b1") and fill down the column. Sort A1:C10 on column A ascending. Then use =vlookup(-e1,\$a\$1:\$c\$10,3).

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