Finding Columns of a Certain Width

Howard has a need to discover all the columns in a worksheet that are a given width. For instance, he needs to know which columns have a width of 3.6.

This can be done by using a macro. One of the properties your macro can access is the width of each column. This means that you can step through the columns and check those widths against the desired width (3.6) in the following manner:

Sub ListColumns()
    Dim dColWidth As Double
    Dim sMsg As String
    Dim x As Integer

    dColWidth = 3.6
    sMsg = ""
    For x = 1 To ActiveSheet.Columns.Count
        If Columns(x).ColumnWidth = dColWidth Then
            sMsg = sMsg & vbCrLf & x
        End If
    Next
    If sMsg = "" Then
        sMsg = "There are no columns with" & _
          vbCrLf & "a width of " & dColWidth
    Else
        sMsg = "The following columns have" & _
          vbCrLf & "a width of " & dColWidth & _
          ":" & vbCrLf & sMsg
    End If
    MsgBox sMsg
End Sub

This macro displays a message box that lists the columns that match the desired width. The macro can be made more robust with some simple changes. For instance, the following example prompts the user for a column width, counts the number of matches, and even compensates if the worksheet is using R1C1 referencing mode.

Sub Find_ColumnWidth()
    Dim Col As Integer          ' Column (loop variable)
    Dim ColsFound As Integer    ' Columns Found Count
    Dim Desired_Width As Double ' Column Width To Find
    Dim OutStr As String        ' Output String
    Dim Title As String         ' Msgbox Title
    Dim I As Integer
    Dim S As String

    ' Find out column width wanted
    S = InputBox("Enter ColumnWidth to find ?", _
      " Find ColumnWidth on " & ActiveSheet.Name)
    Desired_Width = Val(S)
    If Desired_Width = 0 Then Exit Sub

    ' Initialize Columns Found Count and Output String
    ColsFound = 0
    OutStr = ""

    For Col = 1 To ActiveSheet.Columns.Count
        If Columns(Col).ColumnWidth = Desired_Width Then
            ColsFound = ColsFound + 1

            If Application.ReferenceStyle = 1 Then
                ' Using "A1" format
                S = Cells(1, Col).Address(ReferenceStyle:=xlA1)
                S = Mid(S, 2, Len(S) - 3)
            Else
                ' Using "R1C1" format
                S = Trim(Str(Col))
            End If
            OutStr = OutStr & S & vbCrLf
        End If
    Next

    ' Construct MsgBox Title string
    Title = "Width=" & Desired_Width _
      & " on " & ColsFound & " column" _
      & Left("s", - (ColsFound > 1)) & " "

    If ColsFound = 0 Then
        OutStr = "No matches found"
    End If

    MsgBox OutStr, vbOKOnly, Title
End Sub